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Mathematics 19 Online
OpenStudy (brinazarski):

Am I using the right equations? Determine the number of possible outcomes when making a 7-character license plate using the letters of the alphabet and the digits 1-4 if the first 3 characters must be non-repeating letters and the remaining 4 are digits that may repeat. 26C3 x 16C4

OpenStudy (campbell_st):

so there are 26 + 4 choices... the 1st 3 without replacement 30 x 39 x28 x 30C4

OpenStudy (anonymous):

I would think 26*25*24*4^4

OpenStudy (campbell_st):

that correct... 26 x 25x 24 x4^4

OpenStudy (brinazarski):

I'm pretty confused right now...

OpenStudy (anonymous):

Rationale for the above answer: The first letter can be any of 26. The next can be any of the remaining 25, the next can be any of the remaining 24. Each of the four digits can be any of the four digits available, so those contribute a factor of 4^4.

OpenStudy (anonymous):

I get 3993600.

OpenStudy (brinazarski):

That's the right answer (have the answer key) I'm just trying to figure out how you got there... I get the 26*25*24 etc, which is why I put 26C3... or is there no etc, and it's just 26 x 25 x 24?

OpenStudy (zarkon):

\[26\cdot25\cdot24=\,_{26}P_{3}\]

OpenStudy (brinazarski):

-sigh- I'm so confused. I think I'll just leave this question for tutoring ^^;

OpenStudy (zarkon):

\[26\cdot25\cdot24\ne\,_{26}C_{3}=\frac{26\cdot25\cdot24}{3\cdot2\cdot1}\]

OpenStudy (brinazarski):

True, but why is that example a permutation?

OpenStudy (zarkon):

the order that you pick the letter matters

OpenStudy (brinazarski):

... true :o But then the numbers are C, right? (I can't remember the name of it atm, too tired, but I know what it is lol)

OpenStudy (zarkon):

for 'C' the order does not matter

OpenStudy (brinazarski):

And the numbers may repeat, so the order doesn't matter, right?

OpenStudy (zarkon):

the order does matter.... you get 4x4x4x4

OpenStudy (brinazarski):

But why...?

OpenStudy (zarkon):

why the order matters or why it is 4x4x4x4?

OpenStudy (brinazarski):

Both ^^;

OpenStudy (zarkon):

are ABC1234 and ABC4321 the same license plate?

OpenStudy (brinazarski):

No...

OpenStudy (zarkon):

so the order of the numbers matters

OpenStudy (brinazarski):

x.x... so why 4^4?

OpenStudy (zarkon):

and since you can have repeated numbers..you have 4 choices for the first number , 4 for the second, 4 for the third, and 4 for the fourth. Thus 4x4x4x4 total

OpenStudy (brinazarski):

Ah.... that's true

OpenStudy (brinazarski):

4^4 = 4096, right?

OpenStudy (zarkon):

\[4^4=256\]

OpenStudy (brinazarski):

x_x I don't have my graphing calc, sorry. So do I do 256 x 26P3?

OpenStudy (zarkon):

put 256*26*25*24 into google

OpenStudy (brinazarski):

Mhmm... that's the answer

OpenStudy (brinazarski):

26*25*24 = 26P3, right...?

OpenStudy (zarkon):

yes

OpenStudy (brinazarski):

Okay :) Thank you so much!

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