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\[Solve ~the~equation ~~~tanx=3cotx, giving~all~solutions ~btween~0 ~and~36\]
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on simplification we get cos2x=cos120 thus x=n*pi +60,n*pi - 60 here n is an integrer
\[\tan^2x=3\]
tan^2x = 3 (tanx - sqrt3)(tanx + sqrt3) = 0
tanx= sqrt(3) and tanx =-sqrt(3) \[x=n \pi \pm \]
I got tan^2x=3... But I'm not sure how to get the values between 0 and 36.
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360*
\[x=n \pi \pm \pi/3\]
Use the Unit Circle #TheAmericanWay
Or, follow NSB heh
ans are \[\pi/3 ,2\pi/3 ,4\pi/3, 5 \pi/3\]
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Can't quite follow. Can you show me an example of how to get the answers... They're in degrees I think...
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