Mathematics
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OpenStudy (precal):
Does the Mean Value Theorem apply to
f(x)=(x+1)/x from [1,3]
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OpenStudy (precal):
|dw:1331155544699:dw|
OpenStudy (amistre64):
is it continuous from 1 to 3?
OpenStudy (precal):
yes but continuity does not imply differentiablility
OpenStudy (amistre64):
but it helps ....
OpenStudy (precal):
I know..
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OpenStudy (precal):
I took the derivative and got \[f \prime(x)=\frac{-1}{x^2}\]
OpenStudy (dumbcow):
nevermind
OpenStudy (amistre64):
you have smooth curves, well behaved along intervals except for in that one spot ...
OpenStudy (precal):
I am looking for the c value that the Mean Value Thm guarantees
OpenStudy (amistre64):
what your slope from 1 to 3?
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OpenStudy (precal):
-1/3
OpenStudy (amistre64):
the -x^(-2) Ds to get 2x^(-3)
OpenStudy (amistre64):
when 2x^(-3) = -1/3 you got it
OpenStudy (precal):
I set that equal to the derivative to solve for x
OpenStudy (amistre64):
when x^3 = 6 it looks like
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OpenStudy (amistre64):
-6 as the cace may be
OpenStudy (amistre64):
is the cbrt (-6) in the interval?
OpenStudy (precal):
I got \[x=\sqrt{3}\] for x. Did I do something wrong?
OpenStudy (amistre64):
i mighta did something wrong with these fat little fingers ...
OpenStudy (dumbcow):
i also get sqrt(3) :)
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OpenStudy (amistre64):
your initial function is -x^(-2) right?
2x^(-3) is the derivative ... right?
OpenStudy (amistre64):
i see what im doing, im confusing a few posts in this thing ...
OpenStudy (amistre64):
ill go with sqrt(3) by default then :)
OpenStudy (precal):
ok thanks, I think I will stick with the math and forget the math movies.
OpenStudy (amistre64):
everyone needs a hobby :)
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OpenStudy (precal):
yes, I just don't have time to read anything other than math books. Just not enough time.......