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f(x) = 9x^3 − 27x − 19 x = I got 1, but the homework tells me it is wrong, PLEASE help me out!
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\[27x ^{3} - 27 = 0 and then 27x ^{2} = 27 x ^{2} = 1 x = 1\]
27x^2 - 27 = 0
27x^2 = 27
x^2 = 1
so therefore x = 1????
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could it be (-1,1)
nope
on the other problems they drop the 19 and just use chain rule and solve for x
power*
no, -3,3 isnt right either, im thinking about telling my teacher that she is wrong. im serious ive been in a library for three hours doing homework!
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what do you get for this one f(x) = 4x^3 + 4x^−3
you're finding critical points
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