Question

Write a quadratic equation whose roots are 2 and 5 and whose leading coefficient is 3

Answer 1

They give you the zeros, so you can reconstruct the polynomial
(x-2)(x-5)=0
To get a leading coefficient of 3, we multiply by 3:
3(x-2)(x-5)=0
Now you have to foil it out

Answer 2

\[3x^2-7x+10\] is that it?

Answer 3

n0

Answer 4

now, because if you plug in x=2 and x=5, you will not get 0

Answer 5

no*

Answer 6

\[3x^2-11x+30\]

Answer 7

no, a little closer though

Answer 8

you messed up on the inner part of the foil

Answer 9

outer+inner rather

Answer 10

is that part 17x?

Answer 11

no

Answer 12

foil
(x-2)(x-5), then multiply by 3

Answer 13

first + outer + inner + last

Answer 14

oh wait i messed up its 21x

Answer 15

x*x + x*-5 + -2*x + -2*-5

Answer 16

yea, 3x^2-21x+30

Answer 17

ok thanks

Answer 18

np