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Mathematics 13 Online
OpenStudy (curry):

simplify the following

OpenStudy (angela210793):

?

OpenStudy (curry):

one sec

OpenStudy (angela210793):

kk :)

OpenStudy (curry):

(sin^2 + 2sincos+cos^2)/(sin^2-cos^2) simplify

OpenStudy (curry):

how do u simplify sincos

OpenStudy (anonymous):

that part doesnt, sin^2 + cos^2 =1 so you get 2sincos+1/sin^2-cos^2

OpenStudy (curry):

but it can be implified even more

OpenStudy (anonymous):

numerator= (sin+cos)^2 denominator=(sin+cos)(sin-cos) [difference of squares] sin+cos/sin-cos is as simple as it gets

OpenStudy (anonymous):

MCronin is correct!

OpenStudy (angela210793):

I don't get it..why isn't it (a+b)^2??? Someone explain me plsss

OpenStudy (anonymous):

because sin^2+cos^2 = 1 (sin+cos)^2 != 1

OpenStudy (angela210793):

yessss......ur right...idk wht i was thinking -_-

OpenStudy (anonymous):

lol its all good i messed it up the first time too, imusing this to take a break from diferential equations and brain is not functioningcorrctly

OpenStudy (anonymous):

answer is ctg x.

OpenStudy (curry):

what does sin + cos simplifty too?

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