A ball is thrown into the air with an initial upward velocity of 60ft/s. Its height (h) in feet after t seconds is given by the function h = 16t^2 + 60t + 6. After about how many seconds will the ball hit the ground

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anonymous · Answer

typo here

anonymous · Answer

should be 
$$h = -16t^2 + 60t + 6$$ set 
$$-16t^2 + 60t + 6=0$$ solve for t, because when it hits the ground the height will be 0

anonymous · Answer

yes i understand but how many seconds is it 3 4 5 or 6 thats what it say on my paper

anonymous · Answer

none of those are exact, but it is close to 4

anonymous · Answer

ok thanks