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f g(x) = 3x + 5, what is g–1(x)?
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3x+5= -1 SO that means x=6
If im correct it should :)
g^-1 if any one finds that confusing
if? \[g^{-1}(x)=\frac{x-5}{3}\] original function says "multiply by 3, add 5" inverse says "subtract 5, divide by 3"
like if you were solving \[3x+5=17\] you would subtract 5 and get \[3x=12\] then divide by 3 and get \[x=4\] that is what the inverse function does, take you back to where you started from
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ok , well thats what i got but the way ur explaining it confuses me
g(x)let=y y=3x+5 x=3y-5 3y=x-5 3y/3=x/3-5/3 y=x/3-5/3 g(x)=x/3-5/3
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