Question

x +y +3z=1
4x +4y +12z=4
4x +4y +12z=4
Find x, y, and z.

Answer 1

but we get 0=0 for both

Answer 2

this means that y and z are free variables

Answer 3

that means that you
x +y +3z=1
you can pick any values for z and y
then solve for x

Answer 4

because it has at least one free variable it has an infinite number of solutions (this comes from the fact that you can pick any values for z and y)

Answer 5

Do you understand?

Answer 6

sorry I mean row 2 and 3 are scalar multiple of row 1

Answer 7

yea i see on this problem
thank you very much
these are giving me a really hard time

Answer 8

yup after doing a couple of them you get a hang of it...jsut keep doing problems.