Question

Please help me! 4x/x+3-4=x-8/x-3. How do I find the answers to this? There should be two, I just can't figure out how to solve this with the stupid -4 :(

Answer 1

It says that isnt right

Answer 2

oh crud I messed up lol sorry

Answer 3

4x/(x + 3 - 4) = (x-8)/(x-3)
=
4x(x-3)(x + 3 - 4)/(x + 3 - 4) = (x + 3 - 4)(x-8)(x-3)/(x-3)
=
4x(x-3) = (x + 3 - 4))(x-8)

Answer 4

the answer should look like this: number, number

Answer 5

-4 is seperate

Answer 6

elimante the fractions on both sides by mutliplying both sides of the equation by the denominators

Answer 7

4x(x-3) = (x + 3 - 4)(x-8)
4x^(2) - 12 = -8x + -24 + 32 + x^(2) + 3x - 4x

Answer 8

4x^(2) - 12 = -8x + -24 + 32 + x^(2) + 3x - 4x
=
4x^(2) - 12 = -9x + 8 + x^(2)
=
0 = -9x + 8 + x^(2) - 4x^(2) + 12

0 = -3x^(2) - 9x + 20

Answer 9

now factor

Answer 10

oh crud I didn't look at your problem lol

Answer 11

(4x/(x+3)) + 4(x+3)/(x+3)
=
(4x + 4(x+3))/(x+3)

Answer 12

now just do what I did before to solve

Answer 13

you can multiply the top and the botom of a fraction by the same number (excluding 0) and it wont change the value of the fraction this can be used to add whole numbers to fractions.

To prove this

4(x-1)/(x-1) = 4

Answer 14

Because (x-1)/(x-1) = 1
and 4*1 = 4

Answer 15

(4x + 4(x+3))/(x+3) = x-8/x-3

Can you solve this now?

Answer 16

yes no maybe?

Answer 17

(4x + 4(x+3))/(x+3) = (x-8)/(x-3)

=

(4x + 4)(x-3) = (x-8)(x+3)

Answer 18

do the substraction for the LHS
then do opposite multiplication from the eq given by @cuddlepony :
(4x-4(x+3)) (x-3) = (x+3)(x-8)

Answer 19

I got that wrong too, it was -12,5 :(

Answer 20

show your work

Answer 21

and we will show you where you went wrong