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OpenStudy (anonymous):

Differentiate f(x) = (2x^2 + 2x)/(1 + 2x^2)

OpenStudy (anonymous):

(1+2x^2)*(4x+2)-(2x^2+2x)(4x)/(1+2x^2)^2 and simplify from there, just the quotient rule and chain rule

OpenStudy (anonymous):

oh pellet no sorry the denominator is (1+2x)^2

OpenStudy (anonymous):

[(4x+2)(1+2x)^2-(4+8x)(2x^2-2x)]/(1+2x)^4

OpenStudy (anonymous):

wait wait wait (4x+8x)(2x^2-2x) -- MINUS? why minus

OpenStudy (anonymous):

because thats the quotient rule if f(x)/g(x) then [g(x)*f''(x)-f(x)*g'(x)]/g(x)^2

OpenStudy (anonymous):

uh so it's -(4+8x)(2x^2+2x) which equals -8x^2 - 8x - 16x^3 - 16x^2 ...

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