Ask
your own question, for FREE!
Mathematics
16 Online
let z=ln(2x^2+y; let x,y be functions of t with x(1)=1, y(1)=2, x'(1)=3 y'(1)=4 find dz/dt when t=1, i know that i start with it in the form dz/dt=part(z)/part(x)part(x)/part(t) + part(z)/part(x)part(y)/part(t) just not sure where to go from there
Still Need Help?
Join the QuestionCove community and study together with friends!
find dz/dx and dz/dy dz/dx = 4x/(2x^2+y) dz/dy = 1/(2x^2+y) plug in the given info for when t=1
but how do i find the part(x)/part(t) and part(y)/part(t)? thats the part im stuck on
its given at least for when t=1 x'(1) = 3 y'(1) = 4
thanks, wow not enough coffee today yet i should have seen that, thank you
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Cobrakai:
The walls of life are closing in, I never knew the fight within. I struggled to find the way out, always getting down for the count.
AsianPanda08:
I need help. What's the term for words that sound the same but have different meanings? i'm getting different answers.
Graysonunderwoods:
Have you even been beaten by a wet spaghetti noodle by your girlfriend because sh
Ferrari:
I Have Returned to Writing Music (by me) so if you don't know, I used to write songs on here and post them, some of them were lowkey corny though.
Countless7Echos:
whaa this looks so silly, nothing is funnier then looking at how I draw my hands
7 minutes ago
4 Replies
0 Medals
11 minutes ago
38 Replies
0 Medals
49 minutes ago
48 Replies
1 Medal
1 hour ago
34 Replies
2 Medals
3 minutes ago
21 Replies
1 Medal