Ask
your own question, for FREE!
Mathematics
8 Online
let z=ln(2x^2+y; let x,y be functions of t with x(1)=1, y(1)=2, x'(1)=3 y'(1)=4 find dz/dt when t=1, i know that i start with it in the form dz/dt=part(z)/part(x)part(x)/part(t) + part(z)/part(x)part(y)/part(t) just not sure where to go from there
Still Need Help?
Join the QuestionCove community and study together with friends!
find dz/dx and dz/dy dz/dx = 4x/(2x^2+y) dz/dy = 1/(2x^2+y) plug in the given info for when t=1
but how do i find the part(x)/part(t) and part(y)/part(t)? thats the part im stuck on
its given at least for when t=1 x'(1) = 3 y'(1) = 4
thanks, wow not enough coffee today yet i should have seen that, thank you
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos:
Aye.. I need actually some help on the shading here.. if the light is from above too I just feel something is off.
kaelynw:
tried a lil smt, the arm is off but i like the other stuff
Countless7Echos:
I don't know just no sketch doodle day :p finished a video already so I'm pretty
Ferrari:
Depression Hi, it's me, Jordan (ferrari). It's supposed to be the Fourth of July but I feel kinda depressed and mad at myself for no reason.
6 hours ago
19 Replies
3 Medals
18 hours ago
27 Replies
3 Medals
2 days ago
9 Replies
2 Medals
2 days ago
13 Replies
1 Medal