Question

factor
8a^2b^2c-1^ab^2c-192b^2c

Answer 1

know the answer????????????????

Answer 2

!!!!!!!!!!!!!!!!!!!!!!!

Answer 3

cool

Answer 4

yeah!!!!!!!!!!know the answer???????

Answer 5

What do you think it is? Then I'll help you.

Answer 6

It looks like one of the terms doesn't have an "a" so you can't factor that out. But all of them have b's and c's.

So: the question is, what is the number of b's and c's the terms have in common?

Answer 7

first trying to simplify it by factoring out a term that all three sets have in common

Answer 8

First term: 2 b's and 1 c
Second term: 2 b's and 1 c
Third term: 2 b's and 1 c

I'll leave the rest up to you. Tell me what you think the answer is.

Answer 9

is it
8ab^2c(2b-24)