Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced when 8.23 liters of oxygen gas react with excess hydrogen gas? Show all of the work used to solve this problem.

Unbalanced equation: H2 (g) + O2 (g) H2 O(g)

Question

Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced when 8.23 liters of oxygen gas react with excess hydrogen gas? Show all of the work used to solve this problem. 

Unbalanced equation: H2 (g) + O2 (g)  H2 O(g)

anonymous · Answer

2 H2 (g) + O2 (g) --> 2 H2 O(g) 

Volume of H20 produced: 2 * 8.23 = 16.5 L