Question

( 5x+4y) ^6

Answer 1

expand?

Answer 2

\[(4y)^6 + (4y)^5 \times 5x +(4y)^4 \times (5x)^2 + (4y)^3 \times (5x)^3 \]\[+ (4y)^2 \times (5x)^4 + 4y \times (5x)^5 + (5x)^6\]

Answer 3

You can now expand the brackets even further, by raising each of them to the power they need to be raised by, and by timsing the correct ones with eachother.

Answer 4

just curius... did you use pascal's triangle?

Answer 5

Whoops. No. thanks for that. You also need to use Pascals triangle!

Answer 6

wow, impressive.

Answer 7

So, the first one, you'd times by 1. The second by 6, the third by 15, the fourth by 15, the fifth by 6 and the 6th by 1.

Answer 8

You could also write it out like:

\[\left(\begin{matrix}6 \\ 0\end{matrix}\right) times (4y)^6\] and so on....