factor
63x^2 - 175
show me how to do it step by step please
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OpenStudy (mertsj):
First factor out 7
OpenStudy (mertsj):
Can you do that?
OpenStudy (anonymous):
how where is 7
OpenStudy (mertsj):
It is a factor of 63 and of 175
OpenStudy (mertsj):
7 times 9 = 63
7 times 25 = 175
So factor out the 7
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OpenStudy (anonymous):
oh greatest common factor?
OpenStudy (mertsj):
yes
OpenStudy (anonymous):
greatest common factor is the highest number that goes into both correct
OpenStudy (mertsj):
yes
OpenStudy (anonymous):
ok i did 7(
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OpenStudy (mertsj):
What did you get for the other factor?
OpenStudy (anonymous):
what do you mean i thought its 7
OpenStudy (mertsj):
\[63x^2-175=7(9x^2-25)\]
OpenStudy (mertsj):
Now we see that the other factor is 9x^2-25 which is the difference of two squares.
Can you factor 9x^2-25?
OpenStudy (anonymous):
oooh
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OpenStudy (anonymous):
no
OpenStudy (mertsj):
Can you factor x^2-4?
OpenStudy (anonymous):
2?
OpenStudy (anonymous):
well 3*3=9
OpenStudy (mertsj):
\[x^2-4=(x-2)(x+2)\]
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OpenStudy (mertsj):
\[9x^2-25=(3x-5)(3x+5)\]
OpenStudy (anonymous):
oooh
so basically we find the greatest common factor and then find what goes into 9 then put that in the nfind what goes into 25
OpenStudy (mertsj):
Not quite. You factor out the greatest common factor and then you factor the binomial that remains by recognizing that it is the difference of two squares.
OpenStudy (anonymous):
can you help me with this one.. a^4 - a^2 b^2
OpenStudy (mertsj):
Have you studied in your class that
\[a^2-b^2=(a-b)(a+b)\]
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OpenStudy (anonymous):
yes i understand what we just went over i get it in my own way now can you help me with the one i just posted b4 u commented just that
OpenStudy (anonymous):
can you help me with this one.. a^4 - a^2 b^2
OpenStudy (mertsj):
first factor out the GCF which is a^2
OpenStudy (anonymous):
wait how
OpenStudy (mertsj):
\[a^4-a^2b^2=a^2(\]
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