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if the side of a regular pentagon is a and its diagonal is of length b then a^2/b^2+b^2/a^2 is equal to what
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|dw:1331749392608:dw|
I am assuming you need to use the cosine rule of triangles on this one.
@siddharth i like the AM >= GM argument for the last one . wouldn't have thought of it but i wrote a solution using that one too
how do we get the angles to be 144 and 18
Made a mistake. 72 is the angle with the center of the pentagon. You find it by dividing 360 by five as there are five sides.
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