The vertices of quadrilateral ABCD are A(3,0), B(4,3), C(7,3), D(6,0). (a) Prove by means of coordinate geometry, that quadrilateral ABCD is a parallelogram (b) Prove that ABCD is not a rhombus
(a) the side AB is 3 units in length and BC is 3 units in length... opposite sides are equal and parallel, while AB and CD have length \[AB, CD = \sqrt{10}\] opposite sides equal and parallel ( found by using the distance formula) (b) all side not equal in length... see above for details
|dw:1331753457433:dw| to prove it's a parallelogra, just prove slopes of opposite sides are equal. To prove ABCD is not a rhombus, use the distance formula to find the length of all sides. if they are not all the same length, ABCD is not a rhombus.
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