Question

I am not asking these questions because I need some help, I am asking these questions because I have been helping all of you with your problems and now you need to return the favour.

I am going to set all of you 6 questions on general mathematics. Let's see how many you can get correct!
1) Solve x^2+5x+6 = 0 by factorising.
2) Solve x^2 - 2x + 2 = 0 by completing the square.
3) Solve x^2 - 6x + 13 = 0 by using the quadratic formula.
4) If y = 3x^2, find dy/dx. Also integrate this.
5) If y = 3x + 4 and x = 10, find y.
6) Expand (x-3)(x+3). What is this expression an example of?

Answer 1

I will be giving medals out to everyone who gets the answers correct.

Answer 2

1. x^2+5x+6 = 0
(x+3)(x+2) =0
x=-2 or x=-3

Answer 3

2. x^2 - 2x + 2 = 0
(x^2 -2x+1) +1 =0
(x-1)^2 =-1
(x-1) = i or -i
x = i+1 or x = 1-i

Answer 4

3.
x^2 - 6x + 13 = 0
\[x=[-(-6) \pm \sqrt{(-6)^{2}-4(1)(13)}] / 2\]\[x=(6 \pm \sqrt{(-16} )/ 2\]\[x=(3 \pm 2i)\]

Answer 5

4.
dy/dx = d/dx (3x^2) = 6x
\[\int\limits 3x^2 dx = 3 (1/3) x^3 +C = x^3 +C\]

Answer 6

5.
y = 3x + 4 and x = 10
Put x=10 into y = 3x+4
y= 3(10) +4 = 34

Answer 7

6.
(x-3)(x+3) = x^2 - 9
It is difference of 2 square

Answer 8

Please mark the answers !

Answer 9

I've already given you the medals, apparently! I knew I had given one medal but didn't know I had given the medal for every answer you wrote down! You have got everything right. I need to give you a harder quiz!

Answer 10

thanks