2xy+4x+8y+16 how do you factor this out completely??

Question

tommo_lcfc · Answer

Take 2 out as a common factor to get
$$2(xy + 2x + 4y + 8)$$

You can also take x as a common factor in the first two terms and 4 out as a common factor in the last two terms to get

$$2(x(y + 2) + 4(y + 2))$$

This then gives $$2(x + 4)(y + 2)^2$$.

Don't quote me on that!

anonymous · Answer

lol gotcha

callisto · Answer

starting from second step, it is wrong
2xy+4x+8y+16
= 2(xy +2x +4y+8)
= 2[x(y+2) +4(y+2)]
= 2(x+4)(y+2)

anonymous · Answer

kk thanks again lol its much appreciated

tommo_lcfc · Answer

I told you not to quote me on that answer! :) I thought it wasn't right!

callisto · Answer

i didn't say your name, you told the others only

tommo_lcfc · Answer

Sorry :(

anonymous · Answer

its totally fine lol no worries we all make mistakes you dont even have to and your willingly helpin me out so  im not complainin

anonymous · Answer

start step 1 (2xy+4x) + (8y+16) pair them up..
               2 take common in both like x in first and 4 in the second
             3.. x(2y+4) + 4( 2y+4)
now take only one bracket of (2y+4)  and you will get  
|
(x+4) (2y+4) ....

anonymous · Answer

thanks

anonymous · Answer

you are welcome.