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Mathematics 10 Online
OpenStudy (kingj):

What is the remainder when (2x4 – 3x3 + x2 – 3x – 3) ÷ (x – 2) ? 6 3 –9 –66

myininaya (myininaya):

There is a shortcut and a long way. I will first show you the long way then I will show you the shortcut. :)

myininaya (myininaya):

So we are dividing by x-2 x-2=0 when x=2 so to do synthetic division you set it up like this (and you might need 0 placeholders if you have "terms missing" ,but here we don't have any missing....the exponents are 4,3,2,1,0 those are consecutive and it ends with 0 so we are good) now we look at the coefficients of the top too (those are the numbers in front of the variable part) So we have this: 2| 2 -3 1 -3 -3 | ========================== |

myininaya (myininaya):

2| 2 -3 1 -3 -3 | ========================== 2 |

myininaya (myininaya):

I bring down the 2 that is the first step (I brought the first coefficient down of the top)

myininaya (myininaya):

now take that that 2 and multiply it be that other 2 2| 2 -3 1 -3 -3 | 4 ========================== 2 |

myininaya (myininaya):

add -3 and 4 2| 2 -3 1 -3 -3 | 4 ========================== 2 1 |

myininaya (myininaya):

now whatever those numbers you get when you add you will multiply by that 2 on the outside

myininaya (myininaya):

so we do 2 times 1 2| 2 -3 1 -3 -3 | 4 2 ========================== 2 1 |

myininaya (myininaya):

so what do I do with that 1 and 2?

myininaya (myininaya):

kingj, do you know?

OpenStudy (kingj):

so what would the answer be?

myininaya (myininaya):

I don't give just answers and you should be wanting more than the answer anyways :) It will be fun and helpful for the exam to know

myininaya (myininaya):

2| 2 -3 1 -3 -3 | 4 2 ========================== 2 1 | So this is where I left you See if you can fill in the remaining blanks

myininaya (myininaya):

I will check

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