Question

Whats the solution of these two equations?
2y=8-x
y-2x= -1

Answer 1

there are a few methods that could be implemented to find a solution if it exists

Answer 2

system of equations allegbricially

Answer 3

@Helllo;3 do you know how to solve for y in the first equation?

Answer 4

yes, thats tends to cover a few methods tho

Answer 5

noo , and alsoo i need bothh

Answer 6

Solve for y. Just get y on the left side and everything else on the right. Doesn't matter if there's an x. I'll guide you through this.

Answer 7

like solution ( ) , ( )
the corindatinates

Answer 8

okaay

Answer 9

What do you do to solve for y?

Answer 10

you subtract and do the inverse

Answer 11

2y=8-x

You have 2*y. What do you need to do to get that 2 on the other side?

Answer 12

can you draww it , V.V

Answer 13

you substract 2 from both sides

Answer 14

eq2 might be simpler to solve for y :)

Answer 15

2y/2 = (8-x)/2

Answer 16

l need the solution for both x nd y

Answer 17

helllo, if your just expecting an answer then you really not going to like what we have to offer. if you work thru it with briney youll do better

Answer 18

okay

Answer 19

Yes. And it is a step-by-step process. You have to solve for one variable first. In this case, you get the y on one side and the x along with other terms on the other side.

y = some stuff

plug that into the second equation for y.
y-2x= -1

(some stuff) -2x =-1

You solve for x. You get: x= a number.

You plug that back into the first equation to get y.
2y=8-x

2(a number) = 8-x

Then you solve for x.

Then you're done.

Answer 20

what you meaan im done

Answer 21

Those are the steps to solve in a systems of equations. It's not just a one-step process.

Answer 22

like alice in wonderland; you start at the begining, and when you get to the end ... your done lol

Answer 23

im sorry , but i really dont understand this ,

Answer 24

lol ,

Answer 25

I can guide you through to getting the answer to this one. But after that, throw another system of equations out there and see if you can solve it given the process I just told you.

Answer 26

okayy :)

Answer 27

in order to be good at systems of equations you have to have a firm grasp on how to manipulate a single equation to solve for any particular variable that arises in it

Answer 28

step one, find an equation that would solve for y from one of the 2 that are offerec

Answer 29

what ?

Answer 30

what is offerec

Answer 31

yeah, you reallyhave to read thru the typing mistakes

Answer 32

offered

Answer 33

okay soo list the steps for mee ,

Answer 34

briney listed them

Answer 35

soo i know what to do

Answer 36

im lostt ,,,

Answer 37

me too, this little screen aint good for the site

Answer 38

i see about 2 lines of text :)

Answer 39

okay

Answer 40

draw it for me pleasee

Answer 41

2y=8-x
y-2x= -1

1. Solve for y.

2y = 8-x

To get rid of the two, you have to DIVIDE by 2 on each side.

(2y)/2 = (8-x)/2

y = 8/2 -x/2

y=4 - x/2

2. Plug what you got for y into the "y" in your second equation.

y-2x= -1

(4 - x/2) - 2x = -1

4 -x/2 -2x = -1

-x/2 -4x/2 = -5

-5x/2 = -5

(-2/5)*(-5x/2) = -5(-2/5)

x = 2

3. Plug x=2 into eqn 1.

2y=8-x

2y = 8 -(2)

2y = 6

(2y)/2 = 6/2

y=3

Okay I am sure this is correct. I missed a "-1" in one of my steps. But there you go. 3 steps to finding your solutions.

x=2 and y=3

Answer 42

using a usb keyboard makes the typing easier ...

Answer 43

ohh , nd can yu on britney draw it ,pleasee

Answer 44

I don't have a drawing pad. And if you see my writing in real life, it's bad. On a drawing board with no writing pad = illegible.

Answer 45

I think it would help you a lot more if you watch a youtube vid. I'll find one. If you study the 3-step method and do a ton of problems, it will become really easy.

Answer 46

okay thanks

Answer 47

Along with watching the video, I would suggest writing everything I typed out on a piece of paper. Writing things out helps you learn the material.

Answer 48

okayy

Answer 49

He really gets into solving these at 1:46

http://www.youtube.com/watch?v=cwHR_B9zK7k

Answer 50

okay let me see if it will hlp

Answer 51

help

Answer 52

ooo i seee ,

Answer 53

okay now im going to try myself

Answer 54

Yay! Yeah, PatrickJMT has some really good videos.

Paul's online notes are good too:
http://tutorial.math.lamar.edu/Classes/Alg/SystemsTwoVrble.aspx