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Annette drove to shawnee in 4 hours and drove back in 3 hours. what were her speeds if her speed coming back was 11 mph greater than her speed going?
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Speed = d*time Speed going = d*4 Speed returning = d*3 = speed going+11
what would be the equation?
wait lol speed is distance over time.. omg im an idiot
s_g=d/4 s_r=d/3=s_g+11 d/3=(d/4)+11 4d=3d+132 d=132
Thus: speed going: 132/4= 33 speed returning: (132/3)+11 = 55
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thanks
u in smarter classes?
define smarter classes
u know smarter than the average person
define an average person lol
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someone who is smarter than an ape
oh then: <-- my pic says it all
hahahahahahahahahahahaha
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