Annette drove to shawnee in 4 hours and drove back in 3 hours. what were her speeds if her speed coming back was 11 mph greater than her speed going?

Question

bahrom7893 · Answer

Speed = d*time
Speed going = d*4
Speed returning = d*3 = speed going+11

anonymous · Answer

what would be the equation?

bahrom7893 · Answer

wait lol speed is distance over time.. omg im an idiot

bahrom7893 · Answer

s_g=d/4
s_r=d/3=s_g+11
d/3=(d/4)+11
4d=3d+132
d=132

bahrom7893 · Answer

Thus:
speed going:
132/4= 33
speed returning:
(132/3)+11 = 55

anonymous · Answer

thanks

anonymous · Answer

u in smarter classes?

bahrom7893 · Answer

define smarter classes

anonymous · Answer

u know smarter than the average person

bahrom7893 · Answer

define an average person lol

anonymous · Answer

someone who is smarter than an ape

bahrom7893 · Answer

oh then:
<-- my pic says it all

anonymous · Answer

hahahahahahahahahahahaha