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how do you find the end behavior and number of turning points of y=-5x^3? thanks
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Both ends down ward because a negative ( -5) Third degree polynomial has maximum of number of turning points is 2, however in this case just 1!
so when the number is negetive the maximum number of turning points is only 1?
No, in this case" if you let y = 0, give only 1 value x = 0 => only 1 turning point!
Suppose f(x)= 5 x(x-5)(x- 4) then you have 3 -1 = 2 turning points
what about y=3x^3+4x^2+2x-1?
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That's why the rule says at most 2 turning points, since you need to solve it to see how many real roots!
what about y=3x^3+4x^2+2x-1?
Do you know how to find the root?
This case has no turning point at all!
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