Find the equation of a straight line that has a slope of and is passing through the point . Simplify and write the equation in slope intercept form
a line equation you could follow is \[y _{1}- y = m (x _{1} - x)\]
oops i got that wrong.
i mean \[y - y _{1}=m(x-x _{1})\]
so m is the slope. y1 is the y coordinate of the given point. and x1 is the x coordinate of the given point.
you just plug in the numbers and solve for y.
simply and write the equation in slope intercept form
so if you plug in the numbers and solve for y, y should equal mx + b
i don't know how to write it in simple form
i think the slope intercept form, y=mx + b, is the already the simplified form (:
how would i write it m=2/3 -2,-4 in slope intercept form
if you plug in those numbers to the first equation i gave you, you would get y+4=(2/3)(x+2)
thank you
to simplify that, you multiply the (2/3) with x and with 2. then you subtract 4 from both sides. no problem !
what
if you want to get y by itself on the left side. thats what you would do. so y= (2/3)x - (8/3) that is your final answer.
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