Question

derivate y=1nx/2x-1

Answer 1

is it

\[y = 1nx/(2x -1) \]

or

\[y = \ln(x)/(2x -1)\]

Answer 2

its y=1nx/(2x-1)

Answer 3

well its quotient rule

u = 1nx du/dx = n

v = 2x -1 dv/dx = 2

\[dy/dx =( v \times du/dx - u \times dv/dx)/(v)^2\]

\[dy/dx = ((1nx)\times 2 - (2x -1)\times n)/(1nx)^2\]

Answer 4

this simplifes

\[dy/dx = (2nx - 2nx + n)/n^2x^2 = 1/nx^2\]

Answer 5

thanx so much!