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Mathematics 6 Online
OpenStudy (anonymous):

Which of the following is the simplified form of the y^2 + y - 12 / y^2 - 9

jhonyy9 (jhonyy9):

(y+4)(y-3) --------- (y-3)(y+3)

jhonyy9 (jhonyy9):

simplifie

jhonyy9 (jhonyy9):

and will get the result

OpenStudy (anonymous):

You can factorise the top of the equation to (y+4)(y-3) and the bottom to (y-3)(y+3) Note that one of the brackets above is equal to one on the bottom (i.e. the (y-3)), hence these will cancel. This leaves you with (y+4)/(y+3)

OpenStudy (anonymous):

ok but how do i find out the restriction thats the part i dont get

jhonyy9 (jhonyy9):

so the restriction can being x not can be never +/-3 so because than the denominator will be zero and than the fraction is undefined

jhonyy9 (jhonyy9):

ok ?

OpenStudy (anonymous):

ok..now say that in english

OpenStudy (anonymous):

the answer is x+4 over x+3 with a restriction of -3 ?

jhonyy9 (jhonyy9):

so we know that when the denominator of a fraction is zero so than this fraction is undefined -- right ?

OpenStudy (anonymous):

can u just draw it because ur not making sence

jhonyy9 (jhonyy9):

check it please your exersice

jhonyy9 (jhonyy9):

so there is in denominator y^2 -9 yes ?

OpenStudy (anonymous):

thats not what im asking u!!! none of that has to do with the restriction!!

jhonyy9 (jhonyy9):

before all the first step need to be making the restriction

jhonyy9 (jhonyy9):

and after you can continueing the calcules

jhonyy9 (jhonyy9):

so the fisrt step is to push that y not can be never values +/- 3

OpenStudy (anonymous):

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