Question

Which of the following is the simplified form of 4 y^2 - 9 / 2 y^2- y - 3 ?
what is the restriction?

Answer 1

2y+3 / y + 1 , with the restrictions y ≠ 3/2 and y ≠ 1

Answer 2

or is it -1??

Answer 3

4 y^2 - 9 = (2y-3)(2y+3)
2 y^2- y - 3 = (2y-3)(x+1)
4 y^2 - 9 / 2 y^2- y - 3 = (2y-3)(2y+3) / (2y-3)(x+1) = (2y+3) / (x+1)
for 4 y^2 - 9 / 2 y^2- y - 3 to exist, (2y-3)(x+1) =/= 0
therefore y=/= 3/2 and y=/= -1

Answer 4

ok...what does that even say?