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sorry kk - gotta go - another time
Try these two, that are different forms of the same equation.\[f(x)=3+2a^x\]\[g(x)=3+2(1/a)^{-x}\]Note that a>0, and a is different from one.
A baseline exponential equation (y=a^x) has a y-intercept at (0,1) If I multiply by two, the intercept moves to (0,2). If I add three, as I did above, it moves the whole graph up by three, so the y-intercept is now at (0,5). Similarly, the asymptote is at y=0 for the baseline function. If it is moved up by three (as when I added three above) the asymptote is now at y=3. I hope that answers your question.
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