Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the average slope of the function on this interval.
By the mean value theorem, we know there exists at least one c in the open interval (-4,4) such that f’(c) is equal to this mean slope. For this problem, there are 2 values of c that work. The smaller one and the larger one are?

Question

Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the average slope of the function on this interval.
By the mean value theorem, we know there exists at least one c in the open interval (-4,4) such that f’(c) is equal to this mean slope. For this problem, there are 2 values of c that work. The smaller one and the larger one are?

amistre64 · Answer

f(4)- f(-4)
--------- = average slope of the interval
   4--4

amistre64 · Answer

determine when f'(x) = that value and youll have your cs

anonymous · Answer

i got slope of -5 and c is 0 but that isn't right..

amistre64 · Answer

f' = 6x-5

-5 = 6x-5 when x=0

why isnt that right?

amistre64 · Answer

this might be one of those mean integral things with 1/(b-a) then

amistre64 · Answer

we sure there aint a "^3" in this?

amistre64 · Answer

http://oregonstate.edu/instruct/mth251/cq/Stage7/Lesson/MVT.html