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Mathematics 19 Online
OpenStudy (anonymous):

Prove the identity?

OpenStudy (anonymous):

Using the Trig Identities

OpenStudy (anonymous):

How would I start/do this problem

OpenStudy (ajprincess):

R u sure that it is csc theta. I thnk t shud b csc alpha.

OpenStudy (anonymous):

whenever I do trig identities I get all trig functions in terms of sin and cosine

OpenStudy (anonymous):

So: \[\csc2\alpha = (\sec\alpha \csc\alpha) / (2)\]

OpenStudy (anonymous):

@dpalnc thats what I do typically

OpenStudy (ajprincess):

Do u knw vat is sin 2 alpha?

sam (.sam.):

\[\csc2a=\frac{1}{\sin2a}=\frac{1}{2(\sin~a)(\cos~a)}=\frac{1}{2}\sec(a)\csc(a)\]

OpenStudy (anonymous):

Yes, sin2\alpha is

sam (.sam.):

sin2a=2(sina)(cosa)

OpenStudy (anonymous):

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