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Prove the identity?
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Using the Trig Identities
How would I start/do this problem
R u sure that it is csc theta. I thnk t shud b csc alpha.
whenever I do trig identities I get all trig functions in terms of sin and cosine
So: \[\csc2\alpha = (\sec\alpha \csc\alpha) / (2)\]
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@dpalnc thats what I do typically
Do u knw vat is sin 2 alpha?
\[\csc2a=\frac{1}{\sin2a}=\frac{1}{2(\sin~a)(\cos~a)}=\frac{1}{2}\sec(a)\csc(a)\]
Yes, sin2\alpha is
sin2a=2(sina)(cosa)
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