Question

Circle A has an equation of x^2 + (y + 3)^2 = 16. Where is the center of the circle located?

Answer 1

(0;-3)

Answer 2

see circles are in the form of:
(x-a)^2+(y-b)^2=r^2, where (a;b) is the center of the circle.

Answer 3

would that be in the first quadrant? I'm still a little confused...

Answer 4

nothing is in the first quadrant because this circle has it's center at (0, -3) and the radius is 2. no part of this circle lies in the first quadrant.

Answer 5

Is the center on the x or y axis?

Answer 6

y axis

Answer 7

Can you try to explain how, I don't really get it.

Answer 8

what does the point (0;-3) lie on?