Question

3d^2+8d-3=0

Answer 1

Did you try to factor it?

Answer 2

that is where I am stuck

Answer 3

(3x-1)(x+3)=0

Answer 4

Mertsj is right but just replace it with d
(3d-1)(d+3)

Answer 5

to double check if it's correct u can expand out the brackets again and collect like terms.

Answer 6

I got the d+3=0 that d=-3 but not getting 3d-1=0

Answer 7

got it 1/3

Answer 8

F=-(kmn/d^2) olve for M

Answer 9

-kmn/d^2?

Answer 10

it is a fraction of variables

Answer 11

f(d^2)= -kmn
then f(d^2)/kn= -kmn/kn
then f(d^2)/kn=-m
is that what I should have done?

Answer 12

\[Fd^2=-kmn\]

Answer 13

\[\frac{Fd^2}{-kn}=m\]

Answer 14

so I should have moved the - when dividing - thought I was close at least - thanks

Answer 15

yw

Answer 16

y=25 when x=1/5 inversley? What does this mean?

Answer 17

That is only part of the problem. Post the whole thing.

Answer 18

Find the varation constraint in which y varies inversely as x and the following condition exist. y=25 when x=1/5 k=?

Answer 19

\[y=\frac{k}{x}\]

Answer 20

Rep;ace y with 25 and x with 1/5 and solve for k

Answer 21

k=5

Answer 22

thanks

Answer 23

yw