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\3{^-x{^2}} = 7\ Use common log & two decimal places. Why does book say "no solution?"
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The result is 0.43429
Is the book wrong, then? (that's fine... I'm just confused!)
I guess it is
go figure... Thanks very much! :-)
\[3^{-x ^{2}}=7\]
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Is that the problem?
yes
\[-x ^{2}\ln 3=\ln 7\] \[-x^2=\frac{\ln 7}{\ln 3}=1.77\] \[x^2=-1.77\] Now do you see why there is no solution? x^2 cannot be negative
Ok. That was the answer I came up with, too. Thank you much for this! :-)
yw
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