Determine the equation of the tangent line at the value x = 1 for the function f(x) = -5 x + \frac{10}{x} + 4.

The slope-intercept form of the equation of the tangent line at the value x = 1 is
y = .

Question

Determine the equation of the tangent line at the value x = 1 for the function f(x) = -5 x + \frac{10}{x} + 4.

The slope-intercept form of the equation of the tangent line at the value x = 1 is
y = .

anonymous · Answer

$$ f(x) = -5 x + \frac{10}{x} + 4.$$

anonymous · Answer

$$f'(x)|_{x=1}= - 5 - \frac{10}{x^2} \implies f'(x)|_{x=1} = -5 - 10 =-15$$
$$f(x)|_{x=1} = -5 + 10 + 4 = 9$$
$$y - y_1 = m(x - x_1)$$
$$y-9 = -15(x - 1)$$

anonymous · Answer

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anonymous · Answer

thanks