Question

Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 62° north of west. What is the magnitude of the body's acceleration?

Answer 1

the net force on the body =(9-8sin62)i^+(8cos62)j^
Apply vector method to find the magnitude of the net force.
after it find the acceleration:
acceleration=(magnitude of the net force)/mass of the body.