What is the distance traveled by a car that has a velocity equal to v = 3t^2 + 16 in the time period t = 0 to t = 10. Solve using integration.

Question

anonymous · Answer

i guess you need 
$$\int_0^{10} (3t^2+16)dt$$ right?

anonymous · Answer

car is traveling pretty damned fast at ten seconds you get 316 mph

anonymous · Answer

i have to create my own problem that requires integration. Someone told me to use that example but i guess it's not a good one lol

anonymous · Answer

find the anti derivative of 
$$3t^2+16$$ which is 
$$t^3+16t$$ evaluate at 10 to get your answer (no need to evaluate at 0 because you get 0)

anonymous · Answer

well you could tone it down a little. maybe velocity is 2t+1 might be more reasonable, or make it a rocket ship

anonymous · Answer

no it has to be car, so i'll make it 2t+1

anonymous · Answer

okay

anonymous · Answer

lol can you guys help me make a better problem instead

ash2326 · Answer

Just take 
$$v=3t^2+1\ m/s$$
and you'll get the distance in meters

anonymous · Answer

okay thanks

.sam. · Answer

3t^2+1 is fast too, if t=10s,
then 300m/s, which is ~1000km/h

anonymous · Answer

im just going to try making up a completely new problem