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Graph the inequality on a plane
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\[x+y \le3\]
First graph the line x+y=3. Now choose a point which lies on one side of the line, (say above the line) and look at x+y for that point. If x+y is less than 3 at that point then you can deduce that ALL the points above the line also satisfy the inequality, and so the region is above the line. If the value of x+y at the chosen point is bigger than three, then the points satisfying the inequality will all lie below the line.
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