@LagrangeSon678 can you help with my problem
whats the problem?
Given the linear equation y=-2/7x+3, find the y-coordinates of the points (-7, ), (0, ), and (7, ). Please show all of your work
You have y=-2/7x+3, and you are given three x-values,-7,0,and 7. What you should do is plug in each one of these x values into your given equation, like so: y=-2/7(-7)+3 y=-2/7(0)+3 y=-2/7(7)+3 Evaluateing these will produce the correspoding missing y-values
then what do i do from there that confuses me
replace what you get in the ordered pairs, (-7, ), (0, ), and (7, )
For instance i will do one for you, given (-7, ) i will replace the x in your equation with -7, this gives me: y=-2/7(-7)+3 =2+3 =5 thus y=5, now simply we have (-7,5)
ok
y=2/7(7)+3?
you mean y=-2/7(7)+3, you missed the negative sign, regardless this will give you y=1, (7,1)
then for x=0, y=-2/7(0)+3--->y=3 (0,3)
SO THE NUMBER YOU SUB IS THE NUMBER YOU PUT WIT THE THREE
yes
NOW HOW DID YOU GET THE 1 IN THE PREVIOUS PROBLEM
for (-7, ) ?
FOR THE 7
y=-2/7(7)+3 =-2+3 =-1 Thus, (7,-1)
SO WHAT HAPPENS TO THE TWO 7'S
you were given three ordered pair, like this (x,y). Excpet you where only given the x value. (-7, ?) (0,?) (7,?) So this means that inorder to find the y value, you have to plug the x values into your equation y=-2/7x+3.
RIGHT I GET THAT BUT WHAT HAPPENS WHEN YOU YOU PLUGGED IN THE 7 HOW DID YOU GET TO THE -1
y=-2/7x+3, this is your equation, y=-2/7(7)+3 =-2+3 1
OKAY I SEE NOW THANKS SO MUCH
your welcome
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