Question

Find the solutions in the interval [0,2pi)
2cos3theta=1

Answer 1

is the problem
\[2\cos ^{3}\theta=1\]
or
\[2\cos(3\theta)=1\]

Answer 2

the second one

Answer 3

ok thanks..

Answer 4

cos(3x)=1/2
\[3x=2n \pi \pm \pi/9\]

Answer 5

ok, use what not so bright said but remember to keep within [0, 2pi)

Answer 6

I don't understand what he put..
but I got
theta = pi/6 , 2pi/6
is that right?

Answer 7

no @sportscrazy12

Answer 8

okay.. well I don't know how do this problem

Answer 9

answers are obtained by putting n=1 ,2,3

Answer 10

but where did you get pi/9?

Answer 11

put n=0 as well

Answer 12

well its only looking for the the interval between [0, 2pi)
I don't think I'd need to add integers to 2pi

Answer 13

r u there?

Answer 14

yupp

Answer 15

forget about the problem a bit. what angle should be in place of the ?