Question

HighLevel math: find the measure of the the acute angle between the lines 2x+y = 5 and 3x-2y = 8

Answer 1

create vectors from your slope to play with

Answer 2

a=<2,-1> and b=<2,3>

cos(t) = a.b/|a||b|

Answer 3

I still don't get the expansion

Answer 4

\[cos(t)=\frac{2(2)+-1(3)}{\sqrt{(5)(13)}}\]
\[t=cos^{-1}\left(\frac{2(2)+-1(3)}{\sqrt{(5)(13)}}\right)\]

Answer 5

my "a" is a litle off; I got the components swapped about i believe

Answer 6

2x+y = 5

-2/1 = y/x ... <1,-2>

3x-2y = 8

-3/-2 = y/x ... <2,3>

Answer 7

yeah, .... so to adjust for errors lol

\[cos(t)=\frac{1(2)-2(3)}{\sqrt{(5)(13)}}\]
\[t=cos^{-1}\left(\frac{1(2)-2(3)}{\sqrt{(5)(13)}}\right)\]

looks a little better

Answer 8

Thanks a lot

Answer 9

emm isn the angle supposed to be acute? because you got an obtuse angle