Question

Some clarification would be nice.
Find the center and radius:

Answer 1

\[2x^2-4x+2y^2-16y-12=0\]

Answer 2

I got pretty far in the question but I am stuck near the end.

Answer 3

mother....wow..

Answer 4

It's right after I get to: \[x^2-2x+y^2-8y=6\]

Answer 5

Dude, I don't even know what I'm looking at.

Answer 6

center=(-g,-f) when a,b=1 and radius=(g^2+f^2-c)^.5

Answer 7

\[2x^2-4x+2y^2-16y-12=0\]\[2(x^2-2x)+2(y^2-8y)=12\]\[2(x^2-2x+1)+2(y^2-8y+16)=12+2+16\]\[(x-1)^2+(y-4)^2=15\]Does that help?

Answer 8

I meant\[(x-1)^2+(y-4)^2=23\]

Answer 9

*mind blown* THANKS!

Answer 10

Whoop, I see what I did wrong, I forgot to cancel the variable on the 2x.
Much appreciated!