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What is the slope of a tangent line to f(x) = -2x^2 - 3x + 4 , at x = -2? Show work.
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slope =f'(x) at x=-2
I have no idea how to do this, **EDIT TO QUESTION, or explain what steps I have to take and why(if applicable)
take the first derivative of f(x) f'(x)=-4x - 3 at x=-2 f'(x)=8-3=5 so the slope is 5
Thanks so much, I learned this on khanacademy , but wasn't sure if thats what I was suppose to do.
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