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what is the inverse of y=x^2+3
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is square root of -x+3 the same as the square root of x-3?
You have\[y=x^2+3.\] 1. Switch the variables.\[x=y^2+3\]2. Solve for \(y\).\[y=\pm\sqrt{x-3}.\]
why is it positive & negative?
When you take the square root of something, you have to take into consideration both the positive and negative.
@across what about the inverse of y= -x^2+5
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The concept is the same process; switch it. So x = -y^2 + 5. so x-5 = -y^2. But simply divide by a negative sign so you get -x+5 = y^2. So y = sqrt(-x+5).
*+/- squrt. Sorry about that.
wait so its positive and negative too?
@ilikedtea680 what about this one |dw:1332221336147:dw|
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