Question

Find the Vertex:

Answer 1

\[y=2x^2-4x+8\]

Answer 2

Do you know the formula for the x-coordinate of the vertex?

Answer 3

use x = -b/2a which gives the line of symmetry

x = 4/4 x = 1 is the line of symmetry

substitute into the equation y = 6

vertex at (1, 6) ... I think

Answer 4

\[f(x)=a(x-h)^2+k\]

Answer 5

if you use your method you get

f(x) = 2(x^2 - 2x) + 8

f(x) = 2(x^2 - 2x +1) + 6

f(x) 2(x -1)^2 + 6

same solution just a bit more difficult..

find the line of symmetry and substitute

Answer 6

You could always evaluate \(f'\left(x\right)=4x-4=0\therefore x=1\) and find the coordinate \(\left(x,f\left(x\right)\right)\) for that point.