tan^-1(-1) = ?
7πover4
careful here
my trusty scientific calculator said -45 :DDD
range of arctangent is \[[-\frac{\pi}{2},\frac{\pi}{2}]\]
so it should be \[-\frac{\pi}{4}\]
apart from the angle in quadrant IV, you should also consider the tangent of an angle in quadrant II will also give -negative value. therefore the angles are -π/4 or 3π/4
nope
why?
tangent is periodic with period \[\pi\] so there are an infinite number of numbers whose tangent is -1
hmm got it, thanks
\[\tan^{-1}(-1)\] does not mean SOME NUMBER whose tangent is -1 , it means the number in the itnerval \[[-\frac{\pi}{2},\frac{\pi}{2}]\] whose tangent is -1, and there is only one such number because on that interval tangents is one to one and so the inverse is a function (well defined)
i am typong not so good the mroning
it's fine as long as we understand it.
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