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19/2x + 3/5 = 13/2x
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The X's confuse me
multiply both sides by 10x
95x+6=65x?
x=-1/5
\[\frac{19}{2x}+\frac{3}{5}= \frac{13}{2x}\] let's look at 10x times 19/2x: \[10x \cdot \frac{19}{2x}= \frac{10\cancel{x}19}{2\cancel{x}}=5\cdot 19= 95\]
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do you see that the x's cancel except for 10x * (3/5) ?
Oh! Yes i see that :)
So instead of 95x+6=65x? you should get 95 +6x= 65 right?
-5?
yes.
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we multiplied everything by 10x to get rid of the x's in the denominator. It is a good trick to remember.
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