Question

Use comparison test to determine if it converges or diverges.

Answer 1

\[\int\limits_{1}^{\infty} 1/ \sqrt{x^8+1}\]

Answer 2

Not sure what I would use for the comparison

Answer 3

Is that x^infinity

Answer 4

\[\int\limits_{1}^{\infty}1/x ^{8}+1 < \int\limits_{1}^{\infty}1/x ^{8} = \lim_{x \rightarrow \infty} -1/7x ^{7} = 0\]

Answer 5

no. 8

Answer 6

does the square root matter myko?

Answer 7

o, sry forgot that, but doesn't matter anyway, just include it

Answer 8

So wait does this mean it converges? sorry we were intoduced to this before spring break so barely seen/cant remember

Answer 9

yes

Answer 10

use this test http://en.wikipedia.org/wiki/Integral_test_for_convergence it converges