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Graph the vertex:
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\[y=-x^2-2x\]
I want to guess and say it's about.... (-1,-1) or so?
first coordinate of the vertex is \[-\frac{b}{2a}\] in your case it is \[-\frac{-2}{2\times (-1)}=-1\]
replace x by -1 get \[y=-(-1)^2-2\times (-1)=-1+2=1\]
(1,-1)
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Why wouldn't the y be +1 and the x be -1?
1
Yea... I think it's just (1,-1)
Er (-1,1)*
(1,-1)
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Explain yourself please. :I
gt sme numbers and apply them to the equation and see..
*shurgs* I did... I got (-1,1)...
yeah (1-,1)
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