A circle is shown on the coordinate plane below.

What is the equation of this circle?

x2 + (y + 1)2 = 4

x2 + (y – 1)2 = 2

x2 + (y + 1)2 = 2

x2 + (y – 1)2 = 4

Question

A circle is shown on the coordinate plane below.
 
  
 
What is the equation of this circle?

 x2 + (y + 1)2 = 4

 x2 + (y – 1)2 = 2

 x2 + (y + 1)2 = 2

 x2 + (y – 1)2 = 4

anonymous · Answer

attachment

mysesshou · Answer

Try checking your book for the standard equation. I think it is like $$x^2+y^2=r^2$$  then the (y-1) is a shift up.  There should be rules like that in your book. But, you can also plug in the points (3,0) and (-1,0) which fits the last equation you have listed.
That is my thought...  $$x^2 + (y – 1)^2 = 4$$ where the radius is r=2.

... I think...